X^2+16x-350=0

Solution for X^2+16x-350=0 equation:

X^2+16X-350=0

a = 1; b = 16; c = -350;
Δ = b2-4ac
Δ = 162-4·1·(-350)
Δ = 1656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1656}=\sqrt{36*46}=\sqrt{36}*\sqrt{46}=6\sqrt{46}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-6\sqrt{46}}{2*1}=\frac{-16-6\sqrt{46}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+6\sqrt{46}}{2*1}=\frac{-16+6\sqrt{46}}{2}
$